Optimal. Leaf size=316 \[ \frac{5 (b B-9 A c) \log \left (-\sqrt{2} \sqrt [4]{b} \sqrt [4]{c} \sqrt{x}+\sqrt{b}+\sqrt{c} x\right )}{64 \sqrt{2} b^{13/4} c^{3/4}}-\frac{5 (b B-9 A c) \log \left (\sqrt{2} \sqrt [4]{b} \sqrt [4]{c} \sqrt{x}+\sqrt{b}+\sqrt{c} x\right )}{64 \sqrt{2} b^{13/4} c^{3/4}}-\frac{5 (b B-9 A c) \tan ^{-1}\left (1-\frac{\sqrt{2} \sqrt [4]{c} \sqrt{x}}{\sqrt [4]{b}}\right )}{32 \sqrt{2} b^{13/4} c^{3/4}}+\frac{5 (b B-9 A c) \tan ^{-1}\left (\frac{\sqrt{2} \sqrt [4]{c} \sqrt{x}}{\sqrt [4]{b}}+1\right )}{32 \sqrt{2} b^{13/4} c^{3/4}}-\frac{b B-9 A c}{16 b^2 c \sqrt{x} \left (b+c x^2\right )}+\frac{5 (b B-9 A c)}{16 b^3 c \sqrt{x}}-\frac{b B-A c}{4 b c \sqrt{x} \left (b+c x^2\right )^2} \]
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Rubi [A] time = 0.255955, antiderivative size = 316, normalized size of antiderivative = 1., number of steps used = 14, number of rules used = 11, integrand size = 26, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.423, Rules used = {1584, 457, 290, 325, 329, 297, 1162, 617, 204, 1165, 628} \[ \frac{5 (b B-9 A c) \log \left (-\sqrt{2} \sqrt [4]{b} \sqrt [4]{c} \sqrt{x}+\sqrt{b}+\sqrt{c} x\right )}{64 \sqrt{2} b^{13/4} c^{3/4}}-\frac{5 (b B-9 A c) \log \left (\sqrt{2} \sqrt [4]{b} \sqrt [4]{c} \sqrt{x}+\sqrt{b}+\sqrt{c} x\right )}{64 \sqrt{2} b^{13/4} c^{3/4}}-\frac{5 (b B-9 A c) \tan ^{-1}\left (1-\frac{\sqrt{2} \sqrt [4]{c} \sqrt{x}}{\sqrt [4]{b}}\right )}{32 \sqrt{2} b^{13/4} c^{3/4}}+\frac{5 (b B-9 A c) \tan ^{-1}\left (\frac{\sqrt{2} \sqrt [4]{c} \sqrt{x}}{\sqrt [4]{b}}+1\right )}{32 \sqrt{2} b^{13/4} c^{3/4}}-\frac{b B-9 A c}{16 b^2 c \sqrt{x} \left (b+c x^2\right )}+\frac{5 (b B-9 A c)}{16 b^3 c \sqrt{x}}-\frac{b B-A c}{4 b c \sqrt{x} \left (b+c x^2\right )^2} \]
Antiderivative was successfully verified.
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Rule 1584
Rule 457
Rule 290
Rule 325
Rule 329
Rule 297
Rule 1162
Rule 617
Rule 204
Rule 1165
Rule 628
Rubi steps
\begin{align*} \int \frac{x^{9/2} \left (A+B x^2\right )}{\left (b x^2+c x^4\right )^3} \, dx &=\int \frac{A+B x^2}{x^{3/2} \left (b+c x^2\right )^3} \, dx\\ &=-\frac{b B-A c}{4 b c \sqrt{x} \left (b+c x^2\right )^2}+\frac{\left (-\frac{b B}{2}+\frac{9 A c}{2}\right ) \int \frac{1}{x^{3/2} \left (b+c x^2\right )^2} \, dx}{4 b c}\\ &=-\frac{b B-A c}{4 b c \sqrt{x} \left (b+c x^2\right )^2}-\frac{b B-9 A c}{16 b^2 c \sqrt{x} \left (b+c x^2\right )}-\frac{(5 (b B-9 A c)) \int \frac{1}{x^{3/2} \left (b+c x^2\right )} \, dx}{32 b^2 c}\\ &=\frac{5 (b B-9 A c)}{16 b^3 c \sqrt{x}}-\frac{b B-A c}{4 b c \sqrt{x} \left (b+c x^2\right )^2}-\frac{b B-9 A c}{16 b^2 c \sqrt{x} \left (b+c x^2\right )}+\frac{(5 (b B-9 A c)) \int \frac{\sqrt{x}}{b+c x^2} \, dx}{32 b^3}\\ &=\frac{5 (b B-9 A c)}{16 b^3 c \sqrt{x}}-\frac{b B-A c}{4 b c \sqrt{x} \left (b+c x^2\right )^2}-\frac{b B-9 A c}{16 b^2 c \sqrt{x} \left (b+c x^2\right )}+\frac{(5 (b B-9 A c)) \operatorname{Subst}\left (\int \frac{x^2}{b+c x^4} \, dx,x,\sqrt{x}\right )}{16 b^3}\\ &=\frac{5 (b B-9 A c)}{16 b^3 c \sqrt{x}}-\frac{b B-A c}{4 b c \sqrt{x} \left (b+c x^2\right )^2}-\frac{b B-9 A c}{16 b^2 c \sqrt{x} \left (b+c x^2\right )}-\frac{(5 (b B-9 A c)) \operatorname{Subst}\left (\int \frac{\sqrt{b}-\sqrt{c} x^2}{b+c x^4} \, dx,x,\sqrt{x}\right )}{32 b^3 \sqrt{c}}+\frac{(5 (b B-9 A c)) \operatorname{Subst}\left (\int \frac{\sqrt{b}+\sqrt{c} x^2}{b+c x^4} \, dx,x,\sqrt{x}\right )}{32 b^3 \sqrt{c}}\\ &=\frac{5 (b B-9 A c)}{16 b^3 c \sqrt{x}}-\frac{b B-A c}{4 b c \sqrt{x} \left (b+c x^2\right )^2}-\frac{b B-9 A c}{16 b^2 c \sqrt{x} \left (b+c x^2\right )}+\frac{(5 (b B-9 A c)) \operatorname{Subst}\left (\int \frac{1}{\frac{\sqrt{b}}{\sqrt{c}}-\frac{\sqrt{2} \sqrt [4]{b} x}{\sqrt [4]{c}}+x^2} \, dx,x,\sqrt{x}\right )}{64 b^3 c}+\frac{(5 (b B-9 A c)) \operatorname{Subst}\left (\int \frac{1}{\frac{\sqrt{b}}{\sqrt{c}}+\frac{\sqrt{2} \sqrt [4]{b} x}{\sqrt [4]{c}}+x^2} \, dx,x,\sqrt{x}\right )}{64 b^3 c}+\frac{(5 (b B-9 A c)) \operatorname{Subst}\left (\int \frac{\frac{\sqrt{2} \sqrt [4]{b}}{\sqrt [4]{c}}+2 x}{-\frac{\sqrt{b}}{\sqrt{c}}-\frac{\sqrt{2} \sqrt [4]{b} x}{\sqrt [4]{c}}-x^2} \, dx,x,\sqrt{x}\right )}{64 \sqrt{2} b^{13/4} c^{3/4}}+\frac{(5 (b B-9 A c)) \operatorname{Subst}\left (\int \frac{\frac{\sqrt{2} \sqrt [4]{b}}{\sqrt [4]{c}}-2 x}{-\frac{\sqrt{b}}{\sqrt{c}}+\frac{\sqrt{2} \sqrt [4]{b} x}{\sqrt [4]{c}}-x^2} \, dx,x,\sqrt{x}\right )}{64 \sqrt{2} b^{13/4} c^{3/4}}\\ &=\frac{5 (b B-9 A c)}{16 b^3 c \sqrt{x}}-\frac{b B-A c}{4 b c \sqrt{x} \left (b+c x^2\right )^2}-\frac{b B-9 A c}{16 b^2 c \sqrt{x} \left (b+c x^2\right )}+\frac{5 (b B-9 A c) \log \left (\sqrt{b}-\sqrt{2} \sqrt [4]{b} \sqrt [4]{c} \sqrt{x}+\sqrt{c} x\right )}{64 \sqrt{2} b^{13/4} c^{3/4}}-\frac{5 (b B-9 A c) \log \left (\sqrt{b}+\sqrt{2} \sqrt [4]{b} \sqrt [4]{c} \sqrt{x}+\sqrt{c} x\right )}{64 \sqrt{2} b^{13/4} c^{3/4}}+\frac{(5 (b B-9 A c)) \operatorname{Subst}\left (\int \frac{1}{-1-x^2} \, dx,x,1-\frac{\sqrt{2} \sqrt [4]{c} \sqrt{x}}{\sqrt [4]{b}}\right )}{32 \sqrt{2} b^{13/4} c^{3/4}}-\frac{(5 (b B-9 A c)) \operatorname{Subst}\left (\int \frac{1}{-1-x^2} \, dx,x,1+\frac{\sqrt{2} \sqrt [4]{c} \sqrt{x}}{\sqrt [4]{b}}\right )}{32 \sqrt{2} b^{13/4} c^{3/4}}\\ &=\frac{5 (b B-9 A c)}{16 b^3 c \sqrt{x}}-\frac{b B-A c}{4 b c \sqrt{x} \left (b+c x^2\right )^2}-\frac{b B-9 A c}{16 b^2 c \sqrt{x} \left (b+c x^2\right )}-\frac{5 (b B-9 A c) \tan ^{-1}\left (1-\frac{\sqrt{2} \sqrt [4]{c} \sqrt{x}}{\sqrt [4]{b}}\right )}{32 \sqrt{2} b^{13/4} c^{3/4}}+\frac{5 (b B-9 A c) \tan ^{-1}\left (1+\frac{\sqrt{2} \sqrt [4]{c} \sqrt{x}}{\sqrt [4]{b}}\right )}{32 \sqrt{2} b^{13/4} c^{3/4}}+\frac{5 (b B-9 A c) \log \left (\sqrt{b}-\sqrt{2} \sqrt [4]{b} \sqrt [4]{c} \sqrt{x}+\sqrt{c} x\right )}{64 \sqrt{2} b^{13/4} c^{3/4}}-\frac{5 (b B-9 A c) \log \left (\sqrt{b}+\sqrt{2} \sqrt [4]{b} \sqrt [4]{c} \sqrt{x}+\sqrt{c} x\right )}{64 \sqrt{2} b^{13/4} c^{3/4}}\\ \end{align*}
Mathematica [C] time = 0.204782, size = 147, normalized size = 0.47 \[ \frac{2 x^{3/2} (b B-A c) \, _2F_1\left (\frac{3}{4},3;\frac{7}{4};-\frac{c x^2}{b}\right )}{3 b^4}-\frac{2 A c x^{3/2} \, _2F_1\left (\frac{3}{4},2;\frac{7}{4};-\frac{c x^2}{b}\right )}{3 b^4}-\frac{2 A}{b^3 \sqrt{x}}+\frac{A \sqrt [4]{c} \tan ^{-1}\left (\frac{\sqrt [4]{c} \sqrt{x}}{\sqrt [4]{-b}}\right )}{(-b)^{13/4}}+\frac{A b \sqrt [4]{c} \tanh ^{-1}\left (\frac{\sqrt [4]{c} \sqrt{x}}{\sqrt [4]{-b}}\right )}{(-b)^{17/4}} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.018, size = 363, normalized size = 1.2 \begin{align*} -2\,{\frac{A}{{b}^{3}\sqrt{x}}}-{\frac{13\,A{c}^{2}}{16\,{b}^{3} \left ( c{x}^{2}+b \right ) ^{2}}{x}^{{\frac{7}{2}}}}+{\frac{5\,Bc}{16\,{b}^{2} \left ( c{x}^{2}+b \right ) ^{2}}{x}^{{\frac{7}{2}}}}-{\frac{17\,Ac}{16\,{b}^{2} \left ( c{x}^{2}+b \right ) ^{2}}{x}^{{\frac{3}{2}}}}+{\frac{9\,B}{16\,b \left ( c{x}^{2}+b \right ) ^{2}}{x}^{{\frac{3}{2}}}}-{\frac{45\,\sqrt{2}A}{128\,{b}^{3}}\ln \left ({ \left ( x-\sqrt [4]{{\frac{b}{c}}}\sqrt{x}\sqrt{2}+\sqrt{{\frac{b}{c}}} \right ) \left ( x+\sqrt [4]{{\frac{b}{c}}}\sqrt{x}\sqrt{2}+\sqrt{{\frac{b}{c}}} \right ) ^{-1}} \right ){\frac{1}{\sqrt [4]{{\frac{b}{c}}}}}}-{\frac{45\,\sqrt{2}A}{64\,{b}^{3}}\arctan \left ({\sqrt{2}\sqrt{x}{\frac{1}{\sqrt [4]{{\frac{b}{c}}}}}}+1 \right ){\frac{1}{\sqrt [4]{{\frac{b}{c}}}}}}-{\frac{45\,\sqrt{2}A}{64\,{b}^{3}}\arctan \left ({\sqrt{2}\sqrt{x}{\frac{1}{\sqrt [4]{{\frac{b}{c}}}}}}-1 \right ){\frac{1}{\sqrt [4]{{\frac{b}{c}}}}}}+{\frac{5\,\sqrt{2}B}{128\,{b}^{2}c}\ln \left ({ \left ( x-\sqrt [4]{{\frac{b}{c}}}\sqrt{x}\sqrt{2}+\sqrt{{\frac{b}{c}}} \right ) \left ( x+\sqrt [4]{{\frac{b}{c}}}\sqrt{x}\sqrt{2}+\sqrt{{\frac{b}{c}}} \right ) ^{-1}} \right ){\frac{1}{\sqrt [4]{{\frac{b}{c}}}}}}+{\frac{5\,\sqrt{2}B}{64\,{b}^{2}c}\arctan \left ({\sqrt{2}\sqrt{x}{\frac{1}{\sqrt [4]{{\frac{b}{c}}}}}}+1 \right ){\frac{1}{\sqrt [4]{{\frac{b}{c}}}}}}+{\frac{5\,\sqrt{2}B}{64\,{b}^{2}c}\arctan \left ({\sqrt{2}\sqrt{x}{\frac{1}{\sqrt [4]{{\frac{b}{c}}}}}}-1 \right ){\frac{1}{\sqrt [4]{{\frac{b}{c}}}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 2.73933, size = 2244, normalized size = 7.1 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.39101, size = 405, normalized size = 1.28 \begin{align*} -\frac{2 \, A}{b^{3} \sqrt{x}} + \frac{5 \, B b c x^{\frac{7}{2}} - 13 \, A c^{2} x^{\frac{7}{2}} + 9 \, B b^{2} x^{\frac{3}{2}} - 17 \, A b c x^{\frac{3}{2}}}{16 \,{\left (c x^{2} + b\right )}^{2} b^{3}} + \frac{5 \, \sqrt{2}{\left (\left (b c^{3}\right )^{\frac{3}{4}} B b - 9 \, \left (b c^{3}\right )^{\frac{3}{4}} A c\right )} \arctan \left (\frac{\sqrt{2}{\left (\sqrt{2} \left (\frac{b}{c}\right )^{\frac{1}{4}} + 2 \, \sqrt{x}\right )}}{2 \, \left (\frac{b}{c}\right )^{\frac{1}{4}}}\right )}{64 \, b^{4} c^{3}} + \frac{5 \, \sqrt{2}{\left (\left (b c^{3}\right )^{\frac{3}{4}} B b - 9 \, \left (b c^{3}\right )^{\frac{3}{4}} A c\right )} \arctan \left (-\frac{\sqrt{2}{\left (\sqrt{2} \left (\frac{b}{c}\right )^{\frac{1}{4}} - 2 \, \sqrt{x}\right )}}{2 \, \left (\frac{b}{c}\right )^{\frac{1}{4}}}\right )}{64 \, b^{4} c^{3}} - \frac{5 \, \sqrt{2}{\left (\left (b c^{3}\right )^{\frac{3}{4}} B b - 9 \, \left (b c^{3}\right )^{\frac{3}{4}} A c\right )} \log \left (\sqrt{2} \sqrt{x} \left (\frac{b}{c}\right )^{\frac{1}{4}} + x + \sqrt{\frac{b}{c}}\right )}{128 \, b^{4} c^{3}} + \frac{5 \, \sqrt{2}{\left (\left (b c^{3}\right )^{\frac{3}{4}} B b - 9 \, \left (b c^{3}\right )^{\frac{3}{4}} A c\right )} \log \left (-\sqrt{2} \sqrt{x} \left (\frac{b}{c}\right )^{\frac{1}{4}} + x + \sqrt{\frac{b}{c}}\right )}{128 \, b^{4} c^{3}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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